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raft: simplify truncateAndAppend
truncateAndAppend no need the value of 'after' with subbing one
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parent
8e825de35f
commit
df31eab136
@ -101,23 +101,23 @@ func (u *unstable) restore(s pb.Snapshot) {
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}
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func (u *unstable) truncateAndAppend(ents []pb.Entry) {
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after := ents[0].Index - 1
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after := ents[0].Index
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switch {
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case after == u.offset+uint64(len(u.entries))-1:
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// after is the last index in the u.entries
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case after == u.offset+uint64(len(u.entries)):
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// after is the next index in the u.entries
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// directly append
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u.entries = append(u.entries, ents...)
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case after < u.offset:
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u.logger.Infof("replace the unstable entries from index %d", after+1)
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case after <= u.offset:
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u.logger.Infof("replace the unstable entries from index %d", after)
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// The log is being truncated to before our current offset
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// portion, so set the offset and replace the entries
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u.offset = after + 1
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u.offset = after
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u.entries = ents
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default:
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// truncate to after and copy to u.entries
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// then append
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u.logger.Infof("truncate the unstable entries to index %d", after)
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u.entries = append([]pb.Entry{}, u.slice(u.offset, after+1)...)
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u.logger.Infof("truncate the unstable entries before index %d", after)
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u.entries = append([]pb.Entry{}, u.slice(u.offset, after)...)
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u.entries = append(u.entries, ents...)
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}
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}
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