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Eli Bendersky 2022-08-22 05:58:10 -07:00 committed by GitHub
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@ -103,6 +103,11 @@ Some of the examples demonstrate concurrent code which has a non-deterministic
execution order. It depends on how the Go runtime schedules its goroutines and execution order. It depends on how the Go runtime schedules its goroutines and
may vary by operating system, CPU architecture, or even Go version. may vary by operating system, CPU architecture, or even Go version.
Similarly, examples that iterate over maps may produce items in a different order
from what you're getting on your machine. This is because the order of iteration
over maps in Go is [not specified and is not guaranteed to be the same from one
iteration to the next.](https://go.dev/ref/spec#RangeClause).
It doesn't mean anything is wrong with the example. Typically the code in these It doesn't mean anything is wrong with the example. Typically the code in these
examples will be insensitive to the actual order of the output; if the code is examples will be insensitive to the actual order of the output; if the code is
sensitive to the order - that's probably a bug - so feel free to report it. sensitive to the order - that's probably a bug - so feel free to report it.