Clarify use of buffered channel in the timeouts example.

The buffered channel prevents goroutine leaks in case the
channel doesn't end up being read (as indeed happens to c1).

Updates #207
This commit is contained in:
Eli Bendersky
2019-09-05 13:30:16 -07:00
parent 13b0da17de
commit a34c967eaf
3 changed files with 11 additions and 5 deletions

View File

@@ -12,7 +12,10 @@ func main() {
// For our example, suppose we're executing an external
// call that returns its result on a channel `c1`
// after 2s.
// after 2s. Note that the channel is buffered, so the
// send in the goroutine is nonblocking. This is a
// common pattern to prevent goroutine leaks in case the
// channel is never read.
c1 := make(chan string, 1)
go func() {
time.Sleep(2 * time.Second)

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@@ -1,2 +1,2 @@
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