gobyexample/vendor/pygments/external/markdown-processor.py
2016-12-27 08:10:47 -08:00

68 lines
2.0 KiB
Python

# -*- coding: utf-8 -*-
"""
The Pygments Markdown Preprocessor
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
This fragment is a Markdown_ preprocessor that renders source code
to HTML via Pygments. To use it, invoke Markdown like so::
import markdown
html = markdown.markdown(someText, extensions=[CodeBlockExtension()])
This uses CSS classes by default, so use
``pygmentize -S <some style> -f html > pygments.css``
to create a stylesheet to be added to the website.
You can then highlight source code in your markdown markup::
[sourcecode:lexer]
some code
[/sourcecode]
.. _Markdown: https://pypi.python.org/pypi/Markdown
:copyright: Copyright 2006-2015 by the Pygments team, see AUTHORS.
:license: BSD, see LICENSE for details.
"""
# Options
# ~~~~~~~
# Set to True if you want inline CSS styles instead of classes
INLINESTYLES = False
import re
from markdown.preprocessors import Preprocessor
from markdown.extensions import Extension
from pygments import highlight
from pygments.formatters import HtmlFormatter
from pygments.lexers import get_lexer_by_name, TextLexer
class CodeBlockPreprocessor(Preprocessor):
pattern = re.compile(r'\[sourcecode:(.+?)\](.+?)\[/sourcecode\]', re.S)
formatter = HtmlFormatter(noclasses=INLINESTYLES)
def run(self, lines):
def repl(m):
try:
lexer = get_lexer_by_name(m.group(1))
except ValueError:
lexer = TextLexer()
code = highlight(m.group(2), lexer, self.formatter)
code = code.replace('\n\n', '\n&nbsp;\n').replace('\n', '<br />')
return '\n\n<div class="code">%s</div>\n\n' % code
joined_lines = "\n".join(lines)
joined_lines = self.pattern.sub(repl, joined_lines)
return joined_lines.split("\n")
class CodeBlockExtension(Extension):
def extendMarkdown(self, md, md_globals):
md.preprocessors.add('CodeBlockPreprocessor', CodeBlockPreprocessor(), '_begin')